Nuprl Rule : functionEquality

This rule proved as lemma rule_function_equality_true in file rules/rules_function.v
 at https://github.com/vrahli/NuprlInCoq  

H  ⊢ (x1:a1 ⟶ b1) (x2:a2 ⟶ b2) ∈ Type

  BY functionEquality y
  
  H  ⊢ a1 a2 ∈ Type
  y:a1 ⊢ b1[y/x1] b2[y/x2] ∈ Type



Definitions occuring in rule :  function: x:A ⟶ B[x] equal: t ∈ T universe: Type axiom: Ax

Latex:
H    \mvdash{}  (x1:a1  {}\mrightarrow{}  b1)  =  (x2:a2  {}\mrightarrow{}  b2)

    BY  functionEquality  y
   
    H    \mvdash{}  a1  =  a2
    H  y:a1  \mvdash{}  b1[y/x1]  =  b2[y/x2]



Date html generated: 2016_12_14-AM-08_53_28
Last ObjectModification: 2016_07_08-PM-03_48_57

Theory : rules


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