Nuprl Rule : isect_memberEquality

This rule proved as lemma rule_isect_member_equality_true in file rules/rules_isect2.v
 at https://github.com/vrahli/NuprlInCoq  

H  ⊢ b1 b2 ∈ (⋂x:A. B)

  BY isect_memberEquality !parameter{i:l} ()
  
  z:A ⊢ b1 b2 ∈ B[z/x]
  H  ⊢ A ∈ Type



Definitions occuring in rule :  isect: x:A. B[x] equal: t ∈ T universe: Type axiom: Ax

Latex:
H    \mvdash{}  b1  =  b2

    BY  isect\_memberEquality  !parameter\{i:l\}  z  ()
   
    H  z:A  \mvdash{}  b1  =  b2
    H    \mvdash{}  A  =  A



Date html generated: 2016_12_14-AM-08_53_28
Last ObjectModification: 2016_07_08-PM-03_48_54

Theory : rules


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