Nuprl Rule : lambdaEquality

This rule proved as lemma rule_lambda_equality_true in file rules/rules_function.v
 at https://github.com/vrahli/NuprlInCoq  

H  ⊢ x1.b1) x2.b2) ∈ (x:A ⟶ B)

  BY lambdaEquality !parameter{i:l} ()
  
  z:A @i ⊢ b1[z/x1] b2[z/x2] ∈ B[z/x]
  H  ⊢ A ∈ Type



Definitions occuring in rule :  function: x:A ⟶ B[x] lambda: λx.A[x] equal: t ∈ T universe: Type axiom: Ax

Latex:
H    \mvdash{}  (\mlambda{}x1.b1)  =  (\mlambda{}x2.b2)

    BY  lambdaEquality  !parameter\{i:l\}  z  ()
   
    H  z:A  @i  \mvdash{}  b1[z/x1]  =  b2[z/x2]
    H    \mvdash{}  A  =  A



Date html generated: 2016_12_14-AM-08_53_25
Last ObjectModification: 2016_07_08-PM-03_48_52

Theory : rules


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