Nuprl Rule : axiomSqEquality

This rule proved as lemma rule_cequiv_member_eq_true3 in file rules/rules_squiggle6.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ Ax = Ax ∈ (a ~ b)

  BY axiomSqEquality ()

  H  ⊢ a ~ b

Definitions occuring in rule : equal: s = t ∈ T, sqequal: s ~ t, axiom: Ax

Latex:
H \mvdash{} Ax = Ax BY axiomSqEquality () H \mvdash{} a \msim{} b Date html generated: 2019_06_20-PM-04_11_55 Last ObjectModification: 2018_09_14-AM-11_05_14 Theory : rules Home Index