Nuprl Rule : axiomSqEquality

This rule proved as lemma rule_cequiv_member_eq_true3 in file rules/rules_squiggle6.v
 at https://github.com/vrahli/NuprlInCoq  

H  ⊢ Ax Ax ∈ (a b)

  BY axiomSqEquality ()
  
  H  ⊢ b



Definitions occuring in rule :  equal: t ∈ T sqequal: t axiom: Ax

Latex:
H    \mvdash{}  Ax  =  Ax

    BY  axiomSqEquality  ()
   
    H    \mvdash{}  a  \msim{}  b



Date html generated: 2019_06_20-PM-04_11_55
Last ObjectModification: 2018_09_14-AM-11_05_14

Theory : rules


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